0.17*(0.2-x)=x^2

Solution for 0.17*(0.2-x)=x^2 equation:

0.17(0.2-x)=x^2

We move all terms to the left:

0.17(0.2-x)-(x^2)=0

determiningTheFunctionDomain
-x^2+0.17(0.2-x)=0

We add all the numbers together, and all the variables

-x^2+0.17(-1x+0.2)=0

We add all the numbers together, and all the variables

-1x^2+0.17(-1x+0.2)=0

We multiply parentheses

-1x^2-0.17x+0.034=0

a = -1; b = -0.17; c = +0.034;
Δ = b2-4ac
Δ = -0.172-4·(-1)·0.034
Δ = 0.1649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.17)-\sqrt{0.1649}}{2*-1}=\frac{0.17-\sqrt{0.1649}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.17)+\sqrt{0.1649}}{2*-1}=\frac{0.17+\sqrt{0.1649}}{-2}
$